Validating an ip address in a bash script Black bi sexual chat line

check that all of the inputs are numeric and within 1-255 range. echo "$quad" | grep "\.$" Hi there I lost connectivity to one of our remote systems and when I checked the messages log I found the following: Aug 10 host xntpd: time reset (step) 1.681729 s Aug 16 host ip: WARNING: node "mac address" is using our IP address x.x.x.x on aggr1 Aug 16 host... I need a script that, among other things, presents a menu to the user, checks the user input for an IP address (in quad dotted notation), and then "redirects" (with sed) that IP address to the Firewall script. and on here hoping that someone might be able to offer me some help...

quad=1.1.1.12 QUAD4=`echo "$" | egrep '[0-9] \.[0-9] \.[0-9] \.[0-9] '` echo $QUAD4 this validates ok excepts when I have a test ip address as "1.2.2.1a" it fails to validate if and return me the ip adrees itself. I would really appreciate if anyone could give any suggestion. " -ne "0" ]; then echo "$oct: Not numeric" exit 1 else if [ "$oct" -lt "0" -o "$oct" -gt "255" ]; then echo "$oct: Out of range" exit 1 fi fi done # if we're here, we're validated echo "$quad validates OK! " -ne "0" ]; then echo "$oct: Not numeric" exit 1 else if [ "$oct" -lt "0" -o "$oct" -gt "255" ]; then echo "$oct: Out of range" exit 1 fi fi done # New code from here....

$ip =~ ^[0-9].[0-9].[0-9].[0-9]$ - This part makes sure that IP consists of 4 blocks separated by a dot(.) but every block here is allowed to range from 0 - 999 Since desired range of every block would be 0 - 255, to make sure of that below line can be used.

I am very new to bash script so basically i can not understand it very much so please can any one suggest me ways that i can learn faster.

It seems like a lot of code but it should be significantly faster than using external programs like grep or scripts that are likely to fork.

Single IPv6 zero groups compressed to :: will be treated as invalid.

Sorry if this was asked before but I cant find a solution, except for Windows and regex. I would like to validate a network-address like 192.168.1.0/24, or an IP like 192.168.1.1 .

validating an ip address in a bash script-26validating an ip address in a bash script-90validating an ip address in a bash script-80

00000001 Netmask: 255.255.255.0 = 24 11111111.11111111.11111111. 00000000 Wildcard: 0.0.0.255 00000000.00000000.00000000. 11111111 = Network: 192.168.1.0/24 11000000.10101000.00000001. 00000000 Host Min: 192.168.1.1 11000000.10101000.00000001. 00000001 Host Max: 192.168.1.254 11000000.10101000.00000001. 11111110 Broadcast: 192.168.1.255 11000000.10101000.00000001. 11111111 Hosts/Net: 254 Class C, Private Internet Calling the method with IP Address stored in a variable named my IP.

The use of such representation is strongly discouraged, but technically correct.

There is a note in the code explaining how to alter this behaivour if you wish to allow such addresses. /bin/sh set -e # return nonzero unless

00000001 Netmask: 255.255.255.0 = 24 11111111.11111111.11111111. 00000000 Wildcard: 0.0.0.255 00000000.00000000.00000000. 11111111 = Network: 192.168.1.0/24 11000000.10101000.00000001. 00000000 Host Min: 192.168.1.1 11000000.10101000.00000001. 00000001 Host Max: 192.168.1.254 11000000.10101000.00000001. 11111110 Broadcast: 192.168.1.255 11000000.10101000.00000001. 11111111 Hosts/Net: 254 Class C, Private Internet Calling the method with IP Address stored in a variable named my IP.

The use of such representation is strongly discouraged, but technically correct.

There is a note in the code explaining how to alter this behaivour if you wish to allow such addresses. /bin/sh set -e # return nonzero unless $1 contains only digits, leading zeroes not allowed is_numeric() # return nonzero unless $1 contains only hexadecimal digits is_hex() # return nonzero unless $1 is a valid IPv4 address with optional trailing subnet mask in the format /# tests TEST_PASSES=0 TEST_FAILURES=0 for TEST_IP in 0.0.0.0 255.255.255.255 1.2.3.4/1 1.2.3.4/32 .12 123.123.123.123 101.201.201.109 ;do !

/bin/bash ip="2.100" if "$ip" =~ (([01][0-9]|2[0-4][0-9]|25[0-5])\.([01][0-9]|2[0-4][0-9]|25[0-5])\.([01][0-9]|2[0-4][0-9]|25[0-5])\.([01][0-9]|2[0-4][0-9]|25[0-5]))$ ; then echo "success" else echo "fail" fi #!/bin/bash read -p " ip: " req_ipadr # ip_full=$(echo $req_ipadr | sed -n 's/^\(\(\([1-9][0-9]\?

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